How to solve quadratic congruences

by John on December 14, 2008

Quadratic congruences are much more complex than linear congruences. If you’re interested in the details, see these notes on quadratic congruences.

When I started looking into this, I thought my number theory class years ago covered the details but that I’d forgotten them. Looking back, I see that my instructor and my textbook neglected some cases. Then I looked at a few other references and saw that they also left out some cases. I put together some notes by pulling together information from several incomplete but complementary references.

{ 2 comments… read them below or add one }

1

Alasdair McAndrew 01.05.11 at 14:18

This post just got tweeted as as an “Algebra Fact”. The last line should read “if a= 1 (mod 4) there is no analogous formula.” That’s true, but in that case you would use the Shanks-Tonelli algorithm. Maybe you should provide a link to it!

Just my two cents.

Otherwise a nice, complete and informative post – as your always are. I enjoy them.

cheers,
Alasdair

2

John 01.06.11 at 20:54

Alasdair: Thanks! I’ve updated the page.

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