<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Golden ratio and special angles</title>
	<atom:link href="http://www.johndcook.com/blog/2009/05/16/golden-ratio-and-special-angles/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.johndcook.com/blog/2009/05/16/golden-ratio-and-special-angles/</link>
	<description>The blog of John D. Cook</description>
	<lastBuildDate>Sat, 11 Feb 2012 01:10:06 -0500</lastBuildDate>
	<generator>http://wordpress.org/?v=2.8.4</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
		<item>
		<title>By: Nemo</title>
		<link>http://www.johndcook.com/blog/2009/05/16/golden-ratio-and-special-angles/comment-page-1/#comment-40771</link>
		<dc:creator>Nemo</dc:creator>
		<pubDate>Sat, 26 Jun 2010 14:59:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.johndcook.com/blog/?p=2275#comment-40771</guid>
		<description>I first learned this as a geometric argument.

Let ABC be an isosceles triangle with A=72 degrees, B=36 degrees, C=72 degrees.  Let AB = BC = 1 and CA = x.  We will solve for x with a simple geometric argument.

Draw the angle bisector from A intersecting BC at P.  Observe that angle CAP is 36 degrees, so angle APC is 72 degrees, so triangle CAP is another 72-36-72 isosceles triangle.  Therefore AP = x.

Observe that angle PAB is 36 degrees, so triangle BPA is isosceles, so BP also = x and PC = 1-x.

Since triangle ABC is similar to triangle CAP (both being 36-72-36 isosceles), we have PC/CA = CA/AB, or (1-x)/x = x/1.  This is the formula for the golden ratio; &quot;the smaller is to the larger as the larger is to the whole&quot;...  We wind up with x = 1/&#966;.

Then just apply the Law of Cosines to triangle ABC to get the cosine of 36 degrees in terms of &#966;.  It&#039;s &#966;/2 if I recall correctly.</description>
		<content:encoded><![CDATA[<p>I first learned this as a geometric argument.</p>
<p>Let ABC be an isosceles triangle with A=72 degrees, B=36 degrees, C=72 degrees.  Let AB = BC = 1 and CA = x.  We will solve for x with a simple geometric argument.</p>
<p>Draw the angle bisector from A intersecting BC at P.  Observe that angle CAP is 36 degrees, so angle APC is 72 degrees, so triangle CAP is another 72-36-72 isosceles triangle.  Therefore AP = x.</p>
<p>Observe that angle PAB is 36 degrees, so triangle BPA is isosceles, so BP also = x and PC = 1-x.</p>
<p>Since triangle ABC is similar to triangle CAP (both being 36-72-36 isosceles), we have PC/CA = CA/AB, or (1-x)/x = x/1.  This is the formula for the golden ratio; &#8220;the smaller is to the larger as the larger is to the whole&#8221;&#8230;  We wind up with x = 1/&phi;.</p>
<p>Then just apply the Law of Cosines to triangle ABC to get the cosine of 36 degrees in terms of &phi;.  It&#8217;s &phi;/2 if I recall correctly.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Math Teachers at Play #8 &#124;</title>
		<link>http://www.johndcook.com/blog/2009/05/16/golden-ratio-and-special-angles/comment-page-1/#comment-21918</link>
		<dc:creator>Math Teachers at Play #8 &#124;</dc:creator>
		<pubDate>Sun, 02 Aug 2009 07:05:05 +0000</pubDate>
		<guid isPermaLink="false">http://www.johndcook.com/blog/?p=2275#comment-21918</guid>
		<description>[...] John Cook explores a few more tidbits about the golden ratio in Golden ratio and special angles. [...]</description>
		<content:encoded><![CDATA[<p>[...] John Cook explores a few more tidbits about the golden ratio in Golden ratio and special angles. [...]</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Math Teachers at Play #8 &#171; Let&#8217;s Play Math!</title>
		<link>http://www.johndcook.com/blog/2009/05/16/golden-ratio-and-special-angles/comment-page-1/#comment-18266</link>
		<dc:creator>Math Teachers at Play #8 &#171; Let&#8217;s Play Math!</dc:creator>
		<pubDate>Fri, 29 May 2009 11:23:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.johndcook.com/blog/?p=2275#comment-18266</guid>
		<description>[...] John Cook explores a few more tidbits about the golden ratio in Golden ratio and special angles. [...]</description>
		<content:encoded><![CDATA[<p>[...] John Cook explores a few more tidbits about the golden ratio in Golden ratio and special angles. [...]</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: kiwi</title>
		<link>http://www.johndcook.com/blog/2009/05/16/golden-ratio-and-special-angles/comment-page-1/#comment-17622</link>
		<dc:creator>kiwi</dc:creator>
		<pubDate>Sun, 17 May 2009 18:13:28 +0000</pubDate>
		<guid isPermaLink="false">http://www.johndcook.com/blog/?p=2275#comment-17622</guid>
		<description>And since you can do 15 degrees as half of 30 degrees, the difference formula will give you 3 degrees and from there you can get all multiplies of 3 degrees.</description>
		<content:encoded><![CDATA[<p>And since you can do 15 degrees as half of 30 degrees, the difference formula will give you 3 degrees and from there you can get all multiplies of 3 degrees.</p>
]]></content:encoded>
	</item>
</channel>
</rss>

<!-- Dynamic Page Served (once) in 0.303 seconds -->

