[{"id":247877,"date":"2026-09-09T09:59:48","date_gmt":"2026-09-09T14:59:48","guid":{"rendered":"https:\/\/www.johndcook.com\/blog\/?p=247877"},"modified":"2026-09-09T09:59:48","modified_gmt":"2026-09-09T14:59:48","slug":"four-colors","status":"publish","type":"post","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/four-colors\/","title":{"rendered":"A 50-year-old computer-assisted proof"},"content":{"rendered":"<p>The idea of using computers to assist with proofs is not new. The first major computer-assisted proof was published in 1976, the proof of the four color theorem by Kenneth Appel and Wolfgang Haken. The authors reduced the proof of the four color theorem to verifying calculations on 1,834 configurations, each checked by a computer program.<\/p>\n<p>The proof was simplified over the years, and formalized in Coq in 2005. Everyone is satisfied that the theorem is true, but there has never been a satisfying proof, one that a human could read and say &#8220;I see now why any map can be colored using only four colors.&#8221; And there may never be one, but see <a href=\"https:\/\/www.johndcook.com\/blog\/2013\/09\/04\/homework-problems-for-2090\/\">this post<\/a> for a contrary prediction.<\/p>\n<p>The IBM mainframe that ran the calculations completing the proof of the four color theorem did not generate the proof. It simply executed the FORTRAN program that Haken and Appel (and Koch [1]) gave it.<\/p>\n<p>I don&#8217;t see the recent proof of finite-time blowup for solutions to the Navier-Stokes equations as entirely different. Computers did higher-level tasks for the OpenAI team than the mainframe did for Haken and Appel, and these tasks were not as directly programmed as the tasks that were given to the mainframe, but still machines do what they are told to do.<\/p>\n<h2>Related posts<\/h2>\n<ul>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2013\/07\/19\/the-seven-color-map-theorem\/\">The seven color map theorem<\/a><\/li>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2019\/09\/12\/detecting-typos\/\">Detecting errors with the four color theorem<\/a><\/li>\n<\/ul>\n<p>[1] John A. Koch was a programmer who worked on the four color proof with Haken and Appel. I don&#8217;t know how much credit he deserves, but I suspect it may be more than he was given.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The idea of using computers to assist with proofs is not new. The first major computer-assisted proof was published in 1976, the proof of the four color theorem by Kenneth Appel and Wolfgang Haken. The authors reduced the proof of the four color theorem to verifying calculations on 1,834 configurations, each checked by a computer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[5],"tags":[],"class_list":["post-247877","post","type-post","status-publish","format-standard","hentry","category-computing"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/four-colors\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"John D. Cook | Applied Mathematics Consulting\" \/>\n\t\t<meta property=\"og:type\" content=\"article\" \/>\n\t\t<meta property=\"og:title\" content=\"A 50-year-old computer-assisted proof\" \/>\n\t\t<meta property=\"og:description\" content=\"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.\" \/>\n\t\t<meta property=\"og:url\" content=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/four-colors\/\" \/>\n\t\t<meta property=\"article:published_time\" content=\"2026-09-09T14:59:48+00:00\" \/>\n\t\t<meta property=\"article:modified_time\" content=\"2026-09-09T14:59:48+00:00\" \/>\n\t\t<meta name=\"twitter:card\" content=\"summary\" \/>\n\t\t<meta name=\"twitter:title\" content=\"A 50-year-old computer-assisted proof\" \/>\n\t\t<meta name=\"twitter:description\" content=\"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.\" \/>\n\t\t<meta name=\"twitter:image\" content=\"https:\/\/www.johndcook.com\/blog\/wp-content\/uploads\/2022\/05\/twittercard.png\" \/>\n\t\t<!-- All in One SEO -->\n\n","aioseo_head_json":{"title":"A 50-year-old computer-assisted proof","description":"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.","canonical_url":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/four-colors\/","robots":"max-image-preview:large","keywords":"","webmasterTools":{"miscellaneous":""},"schema":null,"og:locale":"en_US","og:site_name":"John D. Cook | Applied Mathematics Consulting","og:type":"article","og:title":"A 50-year-old computer-assisted proof","og:description":"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.","og:url":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/four-colors\/","article:published_time":"2026-09-09T14:59:48+00:00","article:modified_time":"2026-09-09T14:59:48+00:00","twitter:card":"summary","twitter:title":"A 50-year-old computer-assisted proof","twitter:description":"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.","twitter:image":"https:\/\/www.johndcook.com\/blog\/wp-content\/uploads\/2022\/05\/twittercard.png"},"aioseo_meta_data":{"post_id":"247877","title":null,"description":"Computer-assisted proofs are older than you may imagine. The first major theorem proved with the assistance of a computer was over 50 years ago.","keywords":null,"keyphrases":{"focus":{"keyphrase":"","score":0,"analysis":{"keyphraseInTitle":{"score":0,"maxScore":9,"error":1}}},"additional":[]},"primary_term":null,"canonical_url":null,"og_title":null,"og_description":null,"og_object_type":"default","og_image_type":"default","og_image_url":null,"og_image_width":null,"og_image_height":null,"og_image_custom_url":null,"og_image_custom_fields":null,"og_video":"","og_custom_url":null,"og_article_section":null,"og_article_tags":null,"twitter_use_og":false,"twitter_card":"default","twitter_image_type":"default","twitter_image_url":null,"twitter_image_custom_url":null,"twitter_image_custom_fields":null,"twitter_title":null,"twitter_description":null,"schema":{"blockGraphs":[],"customGraphs":[],"default":{"data":{"Article":[],"Course":[],"Dataset":[],"FAQPage":[],"Movie":[],"Person":[],"Product":[],"ProductReview":[],"Car":[],"Recipe":[],"Service":[],"SoftwareApplication":[],"WebPage":[]},"graphName":"Article","isEnabled":true},"graphs":[]},"schema_type":"default","schema_type_options":null,"pillar_content":false,"robots_default":true,"robots_noindex":false,"robots_noarchive":false,"robots_nosnippet":false,"robots_nofollow":false,"robots_noimageindex":false,"robots_noodp":false,"robots_notranslate":false,"robots_max_snippet":"-1","robots_max_videopreview":"-1","robots_max_imagepreview":"large","priority":null,"frequency":"default","location":null,"local_seo":null,"breadcrumb_settings":null,"limit_modified_date":false,"created":"2026-09-09 14:24:10","updated":"2026-09-09 14:59:48","ai":{"faqs":[],"keyPoints":[],"schemas":[],"titles":[],"descriptions":[],"socialPosts":{"email":{"subject":"","preview":"","content":""},"linkedin":[],"twitter":[],"facebook":[],"instagram":[]}},"seo_analyzer_scan_date":null,"focus_keyword":null,"additional_keywords":null,"truseo_locale":null},"aioseo_breadcrumb":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\" title=\"Home\">Home<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\/category\/computing\/\" title=\"Computing\">Computing<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\tA 50-year-old computer-assisted proof\n\t\t<\/span><\/div>","aioseo_breadcrumb_json":[{"label":"Home","link":"https:\/\/www.johndcook.com\/blog"},{"label":"Computing","link":"https:\/\/www.johndcook.com\/blog\/category\/computing\/"},{"label":"A 50-year-old computer-assisted proof","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/four-colors\/"}],"_links":{"self":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247877","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/comments?post=247877"}],"version-history":[{"count":2,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247877\/revisions"}],"predecessor-version":[{"id":247879,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247877\/revisions\/247879"}],"wp:attachment":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/media?parent=247877"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/categories?post=247877"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/tags?post=247877"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}},{"id":247875,"date":"2026-09-09T09:17:20","date_gmt":"2026-09-09T14:17:20","guid":{"rendered":"https:\/\/www.johndcook.com\/blog\/?p=247875"},"modified":"2026-09-09T09:17:20","modified_gmt":"2026-09-09T14:17:20","slug":"ai-multiplier","status":"publish","type":"post","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/ai-multiplier\/","title":{"rendered":"AI is an intelligence multiplier"},"content":{"rendered":"<p>A rising tide may lift all boats, but the AI tide lifts some boats much more than others.<\/p>\n<p>By all accounts, the best programmers have had the biggest productivity boost from AI. And top tier mathematicians are using AI to settle long-standing mathematical conjectures. AI is a powerful tool, but tools don&#8217;t come to life and make things on their own.<\/p>\n<p>I routinely have naive amateurs send me proofs of open conjectures, and naturally more recent such proofs involve AI. I&#8217;ll get an email saying something like &#8220;I&#8217;ve solved the Collatz conjecture using ChatGPT, but I&#8217;m not a mathematician so I need some help verifying the proof.&#8221; And of course the supposed proof is rubbish.<\/p>\n<p>The recent Navier-Stokes proof is impressive, but AI didn&#8217;t initiate the proof any more than LaTeX did. Nor did a child steer AI into proving the conjecture. Professional mathematicians were able to use AI to pursue their ideas at superhuman speed. But someone without an understanding of the Navier-Stokes problem, and familiarity with recent ideas for approaching the problem, could not have directed AI to produce a proof. <\/p>\n<p>Computer scientists have been saying &#8220;garbage in, garbage out&#8221; from the beginning. A variation on this aphorism for the age of AI would be &#8220;mediocrity in, mediocrity out.&#8221; <\/p>\n","protected":false},"excerpt":{"rendered":"<p>A rising tide may lift all boats, but the AI tide lifts some boats much more than others. By all accounts, the best programmers have had the biggest productivity boost from AI. And top tier mathematicians are using AI to settle long-standing mathematical conjectures. AI is a powerful tool, but tools don&#8217;t come to life [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[260],"tags":[],"class_list":["post-247875","post","type-post","status-publish","format-standard","hentry","category-ai"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"The most productive, most creative, and most intelligent people will benefit the most from AI.\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/ai-multiplier\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"John D. Cook | Applied Mathematics Consulting\" \/>\n\t\t<meta property=\"og:type\" content=\"article\" \/>\n\t\t<meta property=\"og:title\" content=\"AI is an intelligence multiplier\" \/>\n\t\t<meta property=\"og:description\" content=\"The most productive, most creative, and most intelligent people will benefit the most from AI.\" \/>\n\t\t<meta property=\"og:url\" content=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/ai-multiplier\/\" \/>\n\t\t<meta property=\"article:published_time\" content=\"2026-09-09T14:17:20+00:00\" \/>\n\t\t<meta property=\"article:modified_time\" content=\"2026-09-09T14:17:20+00:00\" \/>\n\t\t<meta name=\"twitter:card\" content=\"summary\" \/>\n\t\t<meta name=\"twitter:title\" content=\"AI is an intelligence multiplier\" \/>\n\t\t<meta name=\"twitter:description\" content=\"The most productive, most creative, and most intelligent people will benefit the most from AI.\" \/>\n\t\t<meta name=\"twitter:image\" content=\"https:\/\/www.johndcook.com\/blog\/wp-content\/uploads\/2022\/05\/twittercard.png\" \/>\n\t\t<!-- All in One SEO -->\n\n","aioseo_head_json":{"title":"AI is an intelligence multiplier","description":"The most productive, most creative, and most intelligent people will benefit the most from AI.","canonical_url":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/ai-multiplier\/","robots":"max-image-preview:large","keywords":"","webmasterTools":{"miscellaneous":""},"schema":null,"og:locale":"en_US","og:site_name":"John D. Cook | Applied Mathematics Consulting","og:type":"article","og:title":"AI is an intelligence multiplier","og:description":"The most productive, most creative, and most intelligent people will benefit the most from AI.","og:url":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/ai-multiplier\/","article:published_time":"2026-09-09T14:17:20+00:00","article:modified_time":"2026-09-09T14:17:20+00:00","twitter:card":"summary","twitter:title":"AI is an intelligence multiplier","twitter:description":"The most productive, most creative, and most intelligent people will benefit the most from AI.","twitter:image":"https:\/\/www.johndcook.com\/blog\/wp-content\/uploads\/2022\/05\/twittercard.png"},"aioseo_meta_data":{"post_id":"247875","title":null,"description":"The most productive, most creative, and most intelligent people will benefit the most from AI.","keywords":null,"keyphrases":{"focus":{"keyphrase":"","score":0,"analysis":{"keyphraseInTitle":{"score":0,"maxScore":9,"error":1}}},"additional":[]},"primary_term":null,"canonical_url":null,"og_title":null,"og_description":null,"og_object_type":"default","og_image_type":"default","og_image_url":null,"og_image_width":null,"og_image_height":null,"og_image_custom_url":null,"og_image_custom_fields":null,"og_video":"","og_custom_url":null,"og_article_section":null,"og_article_tags":null,"twitter_use_og":false,"twitter_card":"default","twitter_image_type":"default","twitter_image_url":null,"twitter_image_custom_url":null,"twitter_image_custom_fields":null,"twitter_title":null,"twitter_description":null,"schema":{"blockGraphs":[],"customGraphs":[],"default":{"data":{"Article":[],"Course":[],"Dataset":[],"FAQPage":[],"Movie":[],"Person":[],"Product":[],"ProductReview":[],"Car":[],"Recipe":[],"Service":[],"SoftwareApplication":[],"WebPage":[]},"graphName":"Article","isEnabled":true},"graphs":[]},"schema_type":"default","schema_type_options":null,"pillar_content":false,"robots_default":true,"robots_noindex":false,"robots_noarchive":false,"robots_nosnippet":false,"robots_nofollow":false,"robots_noimageindex":false,"robots_noodp":false,"robots_notranslate":false,"robots_max_snippet":"-1","robots_max_videopreview":"-1","robots_max_imagepreview":"large","priority":null,"frequency":"default","location":null,"local_seo":null,"breadcrumb_settings":null,"limit_modified_date":false,"created":"2026-09-09 13:47:02","updated":"2026-09-09 14:17:21","ai":{"faqs":[],"keyPoints":[],"schemas":[],"titles":[],"descriptions":[],"socialPosts":{"email":{"subject":"","preview":"","content":""},"linkedin":[],"twitter":[],"facebook":[],"instagram":[]}},"seo_analyzer_scan_date":null,"focus_keyword":null,"additional_keywords":null,"truseo_locale":null},"aioseo_breadcrumb":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\" title=\"Home\">Home<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\/category\/ai\/\" title=\"AI\">AI<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\tAI is an intelligence multiplier\n\t\t<\/span><\/div>","aioseo_breadcrumb_json":[{"label":"Home","link":"https:\/\/www.johndcook.com\/blog"},{"label":"AI","link":"https:\/\/www.johndcook.com\/blog\/category\/ai\/"},{"label":"AI is an intelligence 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part of Navier-Stokes no one is talking about"},"content":{"rendered":"<p>Yesterday OpenAI announced a proof that settled a long-standing question about the Navier-Stokes equations from fluid dynamics. The announcement has created a lot of buzz, as one would expect. But there&#8217;s an aspect of OpenAI&#8217;s work that I haven&#8217;t seen anyone talk about: they posted a Lean 4 formal proof at the same time as their conventional human-readable proof.<\/p>\n<p>Quite a few other mathematical conjectures have been settled recently using AI, and these have also been accompanied with formal proofs, using Lean 4 in particular.<\/p>\n<p>Until very recently, generating machine-verifiable formal proofs has been <strong>excruciatingly tedious<\/strong>. In 2005, Henk Barendregt and Freek Wiedijk <a href=\"https:\/\/www.cs.ru.nl\/~freek\/notes\/RSpaper.pdf\">wrote<\/a><\/p>\n<blockquote><p>To give an indication of how much work is needed for formalisation, we estimate that it takes approximately one work-week (five work-days of eight work-hours) to formalise one page from an undergraduate mathematics textbook.<\/p><\/blockquote>\n<p>That was the rule of thumb: <strong>forty hours per page<\/strong>. And this in the context of undergraduate textbooks. Research publications are much denser than textbooks. Furthermore, page 100 of a textbook probably depends mostly on material on pages 1 through 99. A sentence in a research article could cite anything that has been published before.<\/p>\n<p>Say a research article takes 20 times more effort to formalize than page in an undergraduate textbook. Then formalizing the 166-page paper from OpenAI would take 132,800 person-hours. It took OpenAI 17 hours to verify their proof in Lean. I hesitate to use the word &#8220;revolutionary,&#8221; but lowering the cost of anything by <strong>four orders of magnitude<\/strong> is revolutionary.<\/p>\n<p>I&#8217;ve used AI to generate formal proofs to check my work just for a little blog post. I wouldn&#8217;t dream of doing that if I had to pay someone a week&#8217;s salary to check my work.<\/p>\n<p>Formal verification doesn&#8217;t just apply to mathematics. You could, for example, formally verify that a set of security policies are consistent and that, given certain assumptions, they accomplish their purpose. You could formally verify that a smart contract imposes a certain maximum liability. You could verify the correctness of mission-critical algorithms. These problems are easier than formalizing mathematics research, and it is easier to quantify the return on investment.<\/p>\n<h2>Related posts<\/h2>\n<ul>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2025\/12\/24\/automation-and-validation\/\">Automation and validation<\/a><\/li>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2016\/07\/11\/formal-methods-let-you-explore-the-corners\/\">Formal methods let you explore the corners<\/a><\/li>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2020\/12\/03\/formal-proof-roi\/\">When are formal methods worth the effort?<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Yesterday OpenAI announced a proof that settled a long-standing question about the Navier-Stokes equations from fluid dynamics. The announcement has created a lot of buzz, as one would expect. But there&#8217;s an aspect of OpenAI&#8217;s work that I haven&#8217;t seen anyone talk about: they posted a Lean 4 formal proof at the same time as [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[1],"tags":[324],"class_list":["post-247870","post","type-post","status-publish","format-standard","hentry","category-uncategorized","tag-formal-methods"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"When OpenAI released their proof that solutions to the Navier-Stokes equations can blow up in finite time, they also released a formal proof in Lean 4.\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<meta name=\"keywords\" content=\"formal methods\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/formal-method-revolution\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"John D. 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Cook | Applied Mathematics Consulting","og:type":"article","og:title":"The part of Navier-Stokes no one is talking about","og:description":"When OpenAI released their proof that solutions to the Navier-Stokes equations can blow up in finite time, they also released a formal proof in Lean 4.","og:url":"https:\/\/www.johndcook.com\/blog\/2026\/09\/09\/formal-method-revolution\/","article:published_time":"2026-09-09T12:43:36+00:00","article:modified_time":"2026-09-09T12:43:36+00:00","twitter:card":"summary","twitter:title":"The part of Navier-Stokes no one is talking about","twitter:description":"When OpenAI released their proof that solutions to the Navier-Stokes equations can blow up in finite time, they also released a formal proof in Lean 4.","twitter:image":"https:\/\/www.johndcook.com\/blog\/wp-content\/uploads\/2022\/05\/twittercard.png"},"aioseo_meta_data":{"post_id":"247870","title":null,"description":"When OpenAI released their proof that solutions to the Navier-Stokes equations 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11:31:29","updated":"2026-09-09 13:05:58","ai":{"faqs":[],"keyPoints":[],"schemas":[],"titles":[],"descriptions":[],"socialPosts":{"email":{"subject":"","preview":"","content":""},"linkedin":[],"twitter":[],"facebook":[],"instagram":[]}},"seo_analyzer_scan_date":null,"focus_keyword":null,"additional_keywords":null,"truseo_locale":null},"aioseo_breadcrumb":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\" title=\"Home\">Home<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\/category\/uncategorized\/\" title=\"Uncategorized\">Uncategorized<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\tThe part of Navier-Stokes no one is talking 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in the news"},"content":{"rendered":"<p>There are rumors that a long-standing math problem, one of the Millennium Prize problems, has been solved.<\/p>\n<p>The problem concerns technical properties of solutions to the <strong>Navier-Stokes equations<\/strong> [1], a set of equations that describe the dynamics of fluid flow. Popular accounts of the problem are often oversimplified and misleading.<\/p>\n<p>Some reports will speak of the problem as &#8220;solving the Navier-Stokes equations.&#8221; The task is not to write down a closed-form solution, which can&#8217;t be done, or solve the equations numerically, which has been done for decades. The problem is to prove theoretical properties of solutions which are of little interest in practice.<\/p>\n<p>There has been progress toward settling the Navier-Stokes problem. Terence Tao wrote a post on this <a href=\"https:\/\/terrytao.wordpress.com\/2026\/09\/07\/finite-time-blowup-with-smooth-forcing-term-for-the-incompressible-porous-medium-boussinesq-and-incompressible-euler-equations\/\">yesterday<\/a>.<\/p>\n<p>What&#8217;s also\u00a0 interesting is the intrigue around the possible solution. A <a href=\"https:\/\/x.com\/etale27\/status\/2097190864598560892\">post<\/a> this morning says<\/p>\n<blockquote><p>If I am reading this correctly, Tristan Buckmaster is alleging OAI has a resolution of Navier-Stokes \u2026 which maybe used info from Buckmaster and Levent Alp\u00f6ge\u2019s private Codex sessions.<\/p><\/blockquote>\n<p>Buckmaster asked OpenAI whether they used his private sessions and they have not responded. <strong>Update<\/strong>: <a href=\"https:\/\/openai.com\/index\/navier-stokes-solution\/\">Statement<\/a> from OpenAI.<\/p>\n<h2>Personal note<\/h2>\n<p>This topic connects parts of my career spanning decades. My graduate work was in PDEs and I had some interest in the Navier-Stokes equations. Here are some <a href=\"https:\/\/www.johndcook.com\/NavierStokes.pdf\">notes<\/a> I wrote back in the day.<\/p>\n<p>Now I work more with privacy than with PDEs. The question of whether OpenAI uses private data, contradicting their stated policy, is more relevant to my current work than whether the Navier-Stokes equations have global regular solutions.<\/p>\n<h2>Related posts<\/h2>\n<ul>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2014\/08\/04\/engineering-a-waterpark\/\">Engineering a waterpark<\/a><\/li>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/Euler_Lagrange_Equations.pdf\">Euler-Lagrange equations<\/a><\/li>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/data-privacy\/\">Data privacy<\/a><\/li>\n<\/ul>\n<p>[1] I never know whether to say equation or equations. You&#8217;ll hear both. You could think of Navier-Stokes as one vector-valued PDE or three scalar-valued equations.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>There are rumors that a long-standing math problem, one of the Millennium Prize problems, has been solved. The problem concerns technical properties of solutions to the Navier-Stokes equations [1], a set of equations that describe the dynamics of fluid flow. Popular accounts of the problem are often oversimplified and misleading. Some reports will speak of [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[260,9],"tags":[202,47],"class_list":["post-247864","post","type-post","status-publish","format-standard","hentry","category-ai","category-math","tag-artificial-intelligence","tag-differential-equations"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"Navier-Stokes equations. What&#039;s the problem? What progress is being made? 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Heinlein (1907-1988) in his book &#8220;Stranger in a Strange Land.&#8221; In the book it is a transliteration of a Martian word and is said to mean etymologically &#8220;to drink.&#8221; It attained popular use in 1960s-70s counterculture but is perhaps obsolete now except in internet technology circles.<\/p><\/blockquote>\n<p>I don&#8217;t believe anything in the statement above is disputed. And yet Google&#8217;s Ngram Viewer tells a very different story.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium\" src=\"https:\/\/www.johndcook.com\/grok_ngram.png\" width=\"600\" height=\"220\" \/><\/p>\n<p>The plot implies that use of the word\u00a0<em>grok<\/em> had been increasing before Heinlein&#8217;s book came out and is now much more common than it was in the 1970s. Note that the plot ends before the Grok AI came out in late 2023.<\/p>\n<p>Apparently the Ngram data is unreliable, mainly for two reasons: OCR errors and inaccurate date attribution. Presumably the blip around 1900 was due to the former, OCR causing words like <em>crok<\/em> or\u00a0<em>grog<\/em> to be cataloged as\u00a0<em>grok<\/em>. And presumably the rise in usage before 1961 was due to the latter, misattributing the date of sources published after 1961.<\/p>\n<p>The supposed rise in usage before 1961 is interesting. You&#8217;d expect some lag between the time a word circulates in conversation and when it appears in books, but apparently this lag can be smaller than the effect of date misattribution.<\/p>\n<p>Etymonline speculates that <em>grok<\/em> is &#8220;perhaps obsolete now except in internet technology circles.&#8221; That matches my experience. Even in technological circles, the word was uncommon before Grok was released. Maybe it was more common in print than in conversation.<\/p>\n<h2>Related posts<\/h2>\n<p>Previous posts with Ngram stats. The effects are so large that they&#8217;re probably directionally correct after adjusting for a substantial error rate.<\/p>\n<ul>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2021\/04\/18\/duodecimal\/\">Duodecimal vs. Hexadecimal<\/a><\/li>\n<li class=\"link\"><a href=\"https:\/\/www.johndcook.com\/blog\/2013\/06\/07\/orwellian-vs-huxleyian\/\">Orwellian vs. Huxleyian<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>The Online Etymological Dictionary gives the following etymology for\u00a0grok: grok (v.) &#8220;understand empathically,&#8221; 1961, an arbitrary formation by U.S. science fiction writer Robert A. Heinlein (1907-1988) in his book &#8220;Stranger in a Strange Land.&#8221; In the book it is a transliteration of a Martian word and is said to mean etymologically &#8220;to drink.&#8221; It attained [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[1],"tags":[],"class_list":["post-247861","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"An example illustrating the large amount of error in Ngram data.\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/07\/ngram-error-rate\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"John D. 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17:52:02","updated":"2026-09-07 19:32:58","ai":{"faqs":[],"keyPoints":[],"schemas":[],"titles":[],"descriptions":[],"socialPosts":{"email":{"subject":"","preview":"","content":""},"linkedin":[],"twitter":[],"facebook":[],"instagram":[]}},"seo_analyzer_scan_date":null,"focus_keyword":null,"additional_keywords":null,"truseo_locale":null},"aioseo_breadcrumb":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\" title=\"Home\">Home<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\/category\/uncategorized\/\" title=\"Uncategorized\">Uncategorized<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\tNgram error 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of the rank-trace theorem"},"content":{"rendered":"<p>The <a href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/04\/stable-rank\/\">previous post<\/a> discussed the motivation for and application of the rank-trace theorem. This post will give a proof.<\/p>\n<p>Suppose\u00a0<em>A<\/em> is a real symmetric matrix. The rank-trace inequality says<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/www.johndcook.com\/rank_trace1.svg\" alt=\"\\operatorname{rank}(A)\\ge\\frac{(\\operatorname{tr} A)^2}{\\operatorname{tr}(A^2)}\" width=\"143\" height=\"49\" \/><\/p>\n<p>where tr is the trace operator, the sum of the elements along the diagonal of the matrix.<\/p>\n<h2>Terse proof<\/h2>\n<p>Here&#8217;s the proof in a nutshell: diagonalize\u00a0<em>A<\/em> and use the Cauchy-Schwarz inequality.<\/p>\n<h2>Detailed proof<\/h2>\n<p>Now let&#8217;s unpack that. Any real symmetric matrix <em>A<\/em> is similar to a matrix <em>D<\/em> with the eigenvalues of\u00a0<em>A<\/em> along the diagonal.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace2.svg\" alt=\"A = PDP^{-1}\" width=\"91\" height=\"18\" \/><\/p>\n<p>The trace of a matrix stays the same under a similarity transformation, i.e. multiplying by\u00a0<em>P<\/em> on one side and its inverse on the other side. So without loss of generality we may as well assume\u00a0<em>A<\/em> is diagonal.<\/p>\n<p>The rank of a matrix equals the number of non-zero eigenvalues, so a vector containing the non-zero eigenvalues of\u00a0<em>A<\/em><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace3.svg\" alt=\"v = [\\lambda_1, \\lambda_2, \\ldots, \\lambda_r]\" width=\"147\" height=\"17\" \/><\/p>\n<p>has length <em>r<\/em> where <em>r<\/em> is the rank of <em>A<\/em>. Define <em>w<\/em> to be the vector of dimension\u00a0<em>r<\/em> consisting of all 1&#8217;s.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace4.svg\" alt=\"w = [1, 1, \\ldots, 1]\" width=\"130\" height=\"17\" \/><\/p>\n<p>Then by the Cauchy-Schwarz inequality we have<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace6.svg\" alt=\"\\operatorname{tr}(A)^2 = \\langle v, w \\rangle^2 \\leq \\langle v, v \\rangle \\, \\langle w, w \\rangle = r \\operatorname{tr}(A^2)\" width=\"332\" height=\"22\" \/><\/p>\n<h2>Cyclic trace property<\/h2>\n<p>Why should a matrix\u00a0<em>A<\/em> and its diagonalization\u00a0<em>D<\/em> have the same trace?<\/p>\n<p>The trace of a matrix product\u00a0<em>AB<\/em> equals the trace of the product\u00a0<em>BA<\/em>. To prove this, write out matrix products and the traces, then note that the two expressions are equal.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/trace_commute.svg\" alt=\" \\begin{align*} \\operatorname{tr}(AB) &amp;= \\sum_i(AB)_{ii}=\\sum_i\\sum_k A_{ik}B_{ki} \\\\ \\operatorname{tr}(BA) &amp;= \\sum_j(BA)_{jj}=\\sum_j\\sum_k B_{jk}A_{kj} \\end{align*}\" width=\"291\" height=\"98\" \/><\/p>\n<p>Therefore<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace7.svg\" alt=\"\\operatorname{tr}(A) = \\operatorname{tr}((PD)P^{-1}) = \\operatorname{tr}(P^{-1}(PD)) = \\operatorname{tr}(D)\" width=\"351\" height=\"22\" \/><\/p>\n<p>More generally, trace has the cyclic property<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/cycle_trace.svg\" alt=\"\\operatorname{tr}(ABC) = \\operatorname{tr}(CAB) = \\operatorname{tr}(BCA)\" width=\"242\" height=\"18\" \/><\/p>\n<p>However, not all permutations preserve the trace. For example, let<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace8.svg\" alt=\"A=\\begin{pmatrix}0&amp;1\\\\0&amp;0\\end{pmatrix},\\quad B=\\begin{pmatrix}0&amp;0\\\\1&amp;0\\end{pmatrix},\\quad C=\\begin{pmatrix}1&amp;0\\\\0&amp;0\\end{pmatrix}.\" width=\"342\" height=\"48\" \/><\/p>\n<p>Then<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace11.svg\" alt=\"\\operatorname{tr}(ABC) = \\operatorname{tr}\\begin{pmatrix}1&amp;0\\\\0&amp;0\\end{pmatrix} = 1\" width=\"192\" height=\"48\" \/><\/p>\n<p>but<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace10.svg\" alt=\"\\operatorname{tr}(ACB) = \\operatorname{tr}\\begin{pmatrix}0&amp;0\\\\0&amp;0\\end{pmatrix} = 0\" width=\"192\" height=\"48\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>The previous post discussed the motivation for and application of the rank-trace theorem. This post will give a proof. Suppose\u00a0A is a real symmetric matrix. The rank-trace inequality says where tr is the trace operator, the sum of the elements along the diagonal of the matrix. Terse proof Here&#8217;s the proof in a nutshell: diagonalize\u00a0A [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[9],"tags":[198],"class_list":["post-247858","post","type-post","status-publish","format-standard","hentry","category-math","tag-linear-algebra"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"Proof of the rank-trace theorem. 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The cyclic property of the trace operator, and a counterexample to a plausible but false generalization.","og:url":"https:\/\/www.johndcook.com\/blog\/2026\/09\/05\/proof-of-the-rank-trace-theorem\/","article:published_time":"2026-09-05T17:04:13+00:00","article:modified_time":"2026-09-05T17:04:13+00:00","twitter:card":"summary","twitter:title":"Proof of the rank-trace theorem","twitter:description":"Proof of the rank-trace theorem. The cyclic property of the trace operator, and a counterexample to a plausible but false generalization.","twitter:image":"https:\/\/www.johndcook.com\/blog\/wp-content\/uploads\/2022\/05\/twittercard.png"},"aioseo_meta_data":{"post_id":"247858","title":null,"description":"Proof of the rank-trace theorem. The cyclic property of the trace operator, and a counterexample to a plausible but false generalization.","keywords":null,"keyphrases":{"focus":{"keyphrase":"","score":0,"analysis":{"keyphraseInTitle":{"score":0,"maxScore":9,"error":1}}},"additional":[]},"primary_term":null,"canonical_url":null,"og_title":null,"og_description":null,"og_object_type":"default","og_image_type":"default","og_image_url":null,"og_image_width":null,"og_image_height":null,"og_image_custom_url":null,"og_image_custom_fields":null,"og_video":"","og_custom_url":null,"og_article_section":null,"og_article_tags":null,"twitter_use_og":false,"twitter_card":"default","twitter_image_type":"default","twitter_image_url":null,"twitter_image_custom_url":null,"twitter_image_custom_fields":null,"twitter_title":null,"twitter_description":null,"schema":{"blockGraphs":[],"customGraphs":[],"default":{"data":{"Article":[],"Course":[],"Dataset":[],"FAQPage":[],"Movie":[],"Person":[],"Product":[],"ProductReview":[],"Car":[],"Recipe":[],"Service":[],"SoftwareApplication":[],"WebPage":[]},"graphName":"Article","isEnabled":true},"graphs":[]},"schema_type":"default","schema_type_options":null,"pillar_content":false,"robots_default":true,"robots_noindex":false,"robots_noarchive":false,"robots_nosnippet":false,"robots_nofollow":false,"robots_noimageindex":false,"robots_noodp":false,"robots_notranslate":false,"robots_max_snippet":"-1","robots_max_videopreview":"-1","robots_max_imagepreview":"large","priority":null,"frequency":"default","location":null,"local_seo":null,"breadcrumb_settings":null,"limit_modified_date":false,"created":"2026-09-05 15:33:45","updated":"2026-09-05 17:38:00","ai":{"faqs":[],"keyPoints":[],"schemas":[],"titles":[],"descriptions":[],"socialPosts":{"email":{"subject":"","preview":"","content":""},"linkedin":[],"twitter":[],"facebook":[],"instagram":[]}},"seo_analyzer_scan_date":null,"focus_keyword":null,"additional_keywords":null,"truseo_locale":null},"aioseo_breadcrumb":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\" title=\"Home\">Home<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\/category\/math\/\" title=\"Math\">Math<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\tProof of the rank-trace theorem\n\t\t<\/span><\/div>","aioseo_breadcrumb_json":[{"label":"Home","link":"https:\/\/www.johndcook.com\/blog"},{"label":"Math","link":"https:\/\/www.johndcook.com\/blog\/category\/math\/"},{"label":"Proof of the rank-trace theorem","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/05\/proof-of-the-rank-trace-theorem\/"}],"_links":{"self":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247858","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/comments?post=247858"}],"version-history":[{"count":1,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247858\/revisions"}],"predecessor-version":[{"id":247859,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247858\/revisions\/247859"}],"wp:attachment":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/media?parent=247858"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/categories?post=247858"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/tags?post=247858"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}},{"id":247851,"date":"2026-09-04T09:16:16","date_gmt":"2026-09-04T14:16:16","guid":{"rendered":"https:\/\/www.johndcook.com\/blog\/?p=247851"},"modified":"2026-09-05T12:05:41","modified_gmt":"2026-09-05T17:05:41","slug":"stable-rank","status":"publish","type":"post","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/04\/stable-rank\/","title":{"rendered":"Computing a lower bound on matrix rank"},"content":{"rendered":"<p>Suppose you want to know the rank of an <em>n<\/em> \u00d7 <em>n<\/em> matrix <em>A<\/em>, the number of linearly independent rows of\u00a0<em>A<\/em>, or equivalently the number of linearly independent columns. There are at least three difficulties.<\/p>\n<h2>Difficulties in computing rank<\/h2>\n<p>First of all, rank is not a continuous function of a matrix. Since rank is an integer, an arbitrarily small change in the matrix could cause a discrete change in the rank [1]. A small error in computing\u00a0<em>A<\/em> could produce a matrix with a different rank.<\/p>\n<p>Second, finding the rank takes <em>O<\/em>(<em>n<\/em>\u00b3) operations, which may or may not be an issue depending on context.<\/p>\n<p>Third, you may not have the matrix\u00a0<em>A<\/em> in an explicit form. Maybe you&#8217;re able to compute products\u00a0<em>Av<\/em> for vectors\u00a0<em>v<\/em> but it&#8217;s not practical to form the entire matrix\u00a0<em>A<\/em>.<\/p>\n<h2>Rank-trace inequality<\/h2>\n<p>If you don&#8217;t need to know the rank of\u00a0<em>A<\/em> per se, but only need to know whether it is above a certain size, a lower bound on the rank may enough.<\/p>\n<p>Suppose\u00a0<em>A<\/em> is a Hermitian matrix. If\u00a0<em>A<\/em> is real, this means\u00a0<em>A<\/em> is symmetric. If\u00a0<em>A<\/em> is complex, this means\u00a0<em>A<\/em> equals its conjugate transpose. Then the rank-trace inequality says<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/rank_trace1.svg\" alt=\"\\operatorname{rank}(A)\\ge\\frac{(\\operatorname{tr} A)^2}{\\operatorname{tr}(A^2)}\" width=\"143\" height=\"49\" \/><br \/>\nThe quantity on the right hand side is known as the <strong>stable rank<\/strong> of\u00a0<em>A<\/em>. It&#8217;s not a rank in any algebraic sense, but it gives a lower bound on rank. And it solves the three problems listed above. See the <a href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/05\/proof-of-the-rank-trace-theorem\/\">next post<\/a> for a proof of the rank-trace theorem.<\/p>\n<h3>Stability<\/h3>\n<p>First of all, trace\u00a0<em>is<\/em> a continuous function of a matrix, and so stable rank is also a continuous function of a matrix, provided the denominator isn&#8217;t zero. A small change to a matrix only makes a small change to its stable rank. That&#8217;s why stable rank is called stable.<\/p>\n<h3>Efficiency<\/h3>\n<p>Second, although computing rank takes <em>O<\/em>(<em>n<\/em>\u00b3) operations, computing stable rank\u00a0takes only <em>O<\/em>(<em>n<\/em>\u00b2) operations, though this isn&#8217;t immediately obvious.<\/p>\n<p>The trace of <em>A<\/em> takes <em>n<\/em> operations: simply sum the elements on the diagonal of <em>A<\/em>. But how do you take the trace of <em>A<\/em>\u00b2? Squaring <em>A<\/em> takes <em>n<\/em>\u00b3 operations, and so if you had to square <em>A<\/em> to find the trace of <em>A<\/em>\u00b2 the rank-trace inequality would have no efficiency advantage over finding the rank of <em>A<\/em>. But you can compute the trace of <em>A<\/em>\u00b2 via<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"background-color: white;\" src=\"https:\/\/www.johndcook.com\/trace_A2.svg\" alt=\"\\operatorname{tr}(A^2) = \\sum_{i=1}^n \\sum_{j=1}^n |a_{ij}|^2\" width=\"171\" height=\"57\" \/><\/p>\n<h3>Formation<\/h3>\n<p>Now suppose you don&#8217;t have the matrix <em>A<\/em> per se but you do have a way of probing <em>A<\/em>, computing the product of vectors with <em>A<\/em>. Maybe <em>A<\/em> is too large to fit into memory, or explicitly computing the elements of <em>A<\/em> would take too long.<\/p>\n<p>There are Monte Carlo algorithms for estimating the traces of <em>A<\/em> and <em>A<\/em>\u00b2 that could be used together to estimate the stable rank of <em>A<\/em>.<\/p>\n<h2>Demonstration<\/h2>\n<p>The following Python code illustrates the discussion above.<\/p>\n<pre>import numpy as np\r\n\r\nnp.random.seed(20260904)\r\nn = 5\r\nB = np.random.randn(n, n)\r\nA = B.T @ B + 1e-8 * np.eye(n)  # Gram matrix plus a tiny shift =&gt; SPD\r\n\r\nrank_A = np.linalg.matrix_rank(A)\r\ntr_A = np.trace(A)\r\ntr_A2 = np.trace(A @ A) # matrix product \r\nsum_sq = np.sum(A * A) # element-by-element product\r\nstable_rank = (tr_A ** 2) \/ tr_A2\r\n\r\nprint(f\"A =\\n{A}\\n\")\r\nprint(f\"rank(A)              = {rank_A}\")\r\nprint(f\"tr(A)                = {tr_A:.12f}\")\r\nprint(f\"tr(A^2) direct       = {tr_A2:.12f}\")\r\nprint(f\"tr(A^2) indirect     = {sum_sq:.12f}\")\r\nprint(f\"stable rank          = {stable_rank:.12f}\")\r\n<\/pre>\n<p>The code above produces the output below.<\/p>\n<pre>A =\r\n[[ 1.09945682  0.4899665   0.98901845  0.66983113 -1.35006341]\r\n [ 0.4899665   0.98531254  0.35067791  0.89757603 -0.72037507]\r\n [ 0.98901845  0.35067791  4.31233926  0.94556225 -0.54819048]\r\n [ 0.66983113  0.89757603  0.94556225  1.3494295  -1.33840786]\r\n [-1.35006341 -0.72037507 -0.54819048 -1.33840786  3.54858332]]\r\n\r\nrank(A)              = 5\r\ntr(A)                = 11.295121449420\r\ntr(A^2) direct       = 51.035447533673\r\ntr(A^2) indirect     = 51.035447533673\r\nstable rank          = 2.499826585688\r\n<\/pre>\n<p>[1] Topological argument: A map from a connected space (such as \u211d<sup><em>n<\/em>\u00d7<em>n<\/em><\/sup>) onto a discrete space (such as \u2124) cannot be continuous, otherwise the inverse images of the points in the range would partition the connected space into disjoint open sets, violating the definition of a connected space.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Suppose you want to know the rank of an n \u00d7 n matrix A, the number of linearly independent rows of\u00a0A, or equivalently the number of linearly independent columns. There are at least three difficulties. Difficulties in computing rank First of all, rank is not a continuous function of a matrix. Since rank is an [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[5,9],"tags":[198],"class_list":["post-247851","post","type-post","status-publish","format-standard","hentry","category-computing","category-math","tag-linear-algebra"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"Why computing the rank of a matrix can be difficult and how the rank-trace inequality lower bound solves the difficulties if a lower bound is adequate.\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<meta name=\"keywords\" content=\"linear algebra\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/04\/stable-rank\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"John D. 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rank","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/04\/stable-rank\/"}],"_links":{"self":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247851","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/comments?post=247851"}],"version-history":[{"count":6,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247851\/revisions"}],"predecessor-version":[{"id":247860,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/posts\/247851\/revisions\/247860"}],"wp:attachment":[{"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/media?parent=247851"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/categories?post=247851"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.johndcook.com\/blog\/wp-json\/wp\/v2\/tags?post=247851"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}},{"id":247847,"date":"2026-09-03T18:34:41","date_gmt":"2026-09-03T23:34:41","guid":{"rendered":"https:\/\/www.johndcook.com\/blog\/?p=247847"},"modified":"2026-09-04T06:01:12","modified_gmt":"2026-09-04T11:01:12","slug":"hugging-face-easter-egg","status":"publish","type":"post","link":"https:\/\/www.johndcook.com\/blog\/2026\/09\/03\/hugging-face-easter-egg\/","title":{"rendered":"Hugging Face Easter Egg"},"content":{"rendered":"<p>NVIDIA has offered to buy Hugging Face for $12,930,300,000.<\/p>\n<p>129303 is the Unicode code point for the Hugging Face emoj (U+1F917), which you can verify with the following Python code.<\/p>\n<pre>\r\n&gt;&gt;&gt; import unicodedata\r\n&gt;&gt;&gt; 129303 == 0x1F917\r\nTrue\r\n&gt;&gt;&gt; unicodedata.name(chr(0x1F917))\r\n'HUGGING FACE'\r\n<\/pre>\n<p><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/www.johndcook.com\/huggingface.png\" width=\"200\" height=\"200\" alt=\"Hugging Face emoji\" class=\"aligncenter size-medium\" \/><\/p>\n<h2>Related posts<\/h2>\n<ul>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2022\/09\/30\/preventing-emoji\/'>Prevent characters from displaying as emoji<\/a><\/li>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2025\/03\/09\/tengwar\/'>Unicode, Tolkien, and Privacy<\/a><\/li>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2025\/03\/09\/unicode-surrogates\/'>Unicode surrogates<\/a><\/li>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2022\/10\/02\/flags-unicode\/'>Making flags in Unicode<\/a><\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>NVIDIA has offered to buy Hugging Face for $12,930,300,000. 129303 is the Unicode code point for the Hugging Face emoj (U+1F917), which you can verify with the following Python code. &gt;&gt;&gt; import unicodedata &gt;&gt;&gt; 129303 == 0x1F917 True &gt;&gt;&gt; unicodedata.name(chr(0x1F917)) &#8216;HUGGING FACE&#8217; Related posts Prevent characters from displaying as emoji Unicode, Tolkien, and Privacy Unicode [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[1],"tags":[135],"class_list":["post-247847","post","type-post","status-publish","format-standard","hentry","category-uncategorized","tag-unicode"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"Unicode Easter Egg in NVIDIA&#039;s offer to buy Hugging Face\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<meta name=\"keywords\" content=\"unicode\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/09\/03\/hugging-face-easter-egg\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta 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23:15:55","updated":"2026-09-04 11:34:04","ai":{"faqs":[],"keyPoints":[],"schemas":[],"titles":[],"descriptions":[],"socialPosts":{"email":{"subject":"","preview":"","content":""},"linkedin":[],"twitter":[],"facebook":[],"instagram":[]}},"seo_analyzer_scan_date":null,"focus_keyword":null,"additional_keywords":null,"truseo_locale":null},"aioseo_breadcrumb":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\" title=\"Home\">Home<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\t<a href=\"https:\/\/www.johndcook.com\/blog\/category\/uncategorized\/\" title=\"Uncategorized\">Uncategorized<\/a>\n\t\t<\/span><span class=\"aioseo-breadcrumb-separator\">&raquo;<\/span><span class=\"aioseo-breadcrumb\">\n\t\t\tHugging Face Easter 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RSA number factored"},"content":{"rendered":"<p>Eric Lu <a href=\"https:\/\/x.com\/penlume\/status\/2095372672356212876?s=20\">announced<\/a> on X today that he has factored RSA-260, a number <em>N<\/em> with 260 digits (862 bits) that is the product of two large primes [1].<\/p>\n<p>RSA numbers are challenge problems posed to gauge the security of RSA encryption, which rests on the difficulty of factoring large numbers [2]. The naming scheme is confusing because RSA-<em>n<\/em> might have\u00a0<em>n<\/em> digits or\u00a0<em>n<\/em> bits. For example, RSA-768 is smaller than RSA-260 because the former has 768 bits and the latter has 260 digits.<\/p>\n<p>RSA-260 is the largest RSA number factored so far. What does the news of its factorization say about the security of RSA?<\/p>\n<p>Based on equations <a href=\"https:\/\/www.johndcook.com\/blog\/2025\/09\/30\/time-needed-to-factor-large-integers\/\">here<\/a>, an RSA key with 862 bits would have a security level of 74 bits, i.e. the same security level as symmetric encryption with a 74-bit key. The minimum recommended RSA key size now is 2048 bits, which has a security level of 107 bits.<\/p>\n<p>Security levels are on a logarithmic scale: each additional bit of security doubles the effort required to break the encryption by brute force. So breaking a 2048-bit RSA key would take 2<sup>34<\/sup>, roughly 10<sup>10<\/sup>, times more effort than factoring RSA-260. All this depends on numerous assumptions, such as the state of factorization algorithms and the non-existence of CRQC [3].<\/p>\n<h2>Related posts<\/h2>\n<ul>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2019\/02\/11\/rsa-duplication-flaws\/'>RSA implementation flaws<\/a><\/li>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2023\/08\/05\/rsa-private-key\/'>Generating and inspecting an RSA key<\/a><\/li>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2025\/08\/05\/martin-gardners-rsa\/'>Martin Gardner&#8217;s RSA article<\/a><\/li>\n<li class='link'><a href='https:\/\/www.johndcook.com\/blog\/2026\/06\/13\/rsa-munitions-t-shirt\/'>RSA munitions T-shirt<\/a><\/li>\n<\/ul>\n<p>[1] <em>N<\/em> = <em>pq<\/em> = 22112825529529666435281085255026230927612089502470015394413748319128822941402001986512729726569746599085900330031400051170742204560859276357953757185954298838958709229238491006703034124620545784566413664540684214361293017694020846391065875914794251435144458199<\/p>\n<p><em>p<\/em> = 4397328654844826923795068102505872571721883526553349659561256924505973939597593482272505698004801207988043088656411102133523080581<\/p>\n<p><em>q<\/em> = 5028695206842569864686141618253083416610081090075366674776775706538324961364412200138116378509733307971876652984898985905923678379<\/p>\n<p>[2] The ability to efficiently factor large primes would break RSA. It&#8217;s possible that there&#8217;s a way to break RSA without being able to factor large numbers. More on that <a href=\"https:\/\/www.johndcook.com\/blog\/2025\/01\/06\/rsa-factoring\/\">here<\/a>.<\/p>\n<p>[3] Cryptographically-relevant quantum computer. Quantum computers exist, but so far they&#8217;re cryptographically irrelevant. So far quantum computers cannot factor 21 without <a href=\"https:\/\/www.johndcook.com\/blog\/2026\/03\/31\/quantum-y2k\/\">cheating<\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Eric Lu announced on X today that he has factored RSA-260, a number N with 260 digits (862 bits) that is the product of two large primes [1]. RSA numbers are challenge problems posed to gauge the security of RSA encryption, which rests on the difficulty of factoring large numbers [2]. The naming scheme is [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[5],"tags":[43],"class_list":["post-247845","post","type-post","status-publish","format-standard","hentry","category-computing","tag-cryptography"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"A new record has been set for factoring RSA challenge numbers. 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Nearly all the work I do is under an NDA, so I don&#8217;t often get a chance to talk about my projects. This work is public now that it&#8217;s in a patent; I suppose it has been public since the application was published.<\/p>\n<p>Brian did most of the work on the project. My contribution was to mathematically formalize low-level operations on sheets of bits using linear algebra over a binary field. Lots of Hadamard products and outer products, if I remember correctly. When you can reduce computations to algebra, you can prove that a sequence of operations is correct, and you can find optimizations by simplifying expressions.<\/p>\n<p>The patent mentions a programming language called Tartan. I suggested calling it plaid because it used matrices with mask patterns that reminded me of a plaid pattern, and Brian countered saying we should call it Tartan. I like that name better.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter size-medium\" src=\"https:\/\/www.johndcook.com\/tartan2.png\" alt=\"Figure 5B from patent\" width=\"550\" height=\"514\" \/><\/p>\n<p style=\"text-align: center;\">Figure 5B from the patent.<\/p>\n<p>[1] Brian Beckman and John D. Cook. Compiler for a parallel processor. U.S. Patent 12,717,871 B2. Applicant\/Assignee: GSI Technology Inc., Sunnyvale, CA.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>I just found out Brian Beckman and I got a patent on work we did for GSI Technology [1]. Nearly all the work I do is under an NDA, so I don&#8217;t often get a chance to talk about my projects. This work is public now that it&#8217;s in a patent; I suppose it has [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[5],"tags":[198],"class_list":["post-247831","post","type-post","status-publish","format-standard","hentry","category-computing","tag-linear-algebra"],"acf":[],"aioseo_notices":[],"aioseo_head":"\n\t\t<!-- All in One SEO 5.0.1.1 - aioseo.com -->\n\t<meta name=\"description\" content=\"New patent that uses linear algebra over a binary field as part of the formalization of a parallel compiler\" \/>\n\t<meta name=\"robots\" content=\"max-image-preview:large\" \/>\n\t<meta name=\"author\" content=\"John\"\/>\n\t<meta name=\"keywords\" content=\"linear algebra\" \/>\n\t<link rel=\"canonical\" href=\"https:\/\/www.johndcook.com\/blog\/2026\/08\/31\/patented-application-of-linear-algebra\/\" \/>\n\t<meta name=\"generator\" content=\"All in One SEO (AIOSEO) 5.0.1.1\" \/>\n\t\t<meta property=\"og:locale\" content=\"en_US\" \/>\n\t\t<meta property=\"og:site_name\" content=\"John D. 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