Negative damping

An earlier post looked at the effect of damping on free vibrations. We looked at the equation

m u″ + γ u′ + k u = 0

where the coefficients m, γ, and k were all positive. But what if some of these terms are negative?

Let’s assume that m is positive. Otherwise multiply the equation above by −1. What happens if γ or k are negative?

The term γ, when positive, takes energy out of the system. A negative value of γ would be a term that adds energy, a sort of negative damping. The behavior of the solutions is determined by the eigenvalues of the system, that is the roots of the equation

m x2 + γ x + k = 0.

If γ is negative, the eigenvalues have positive real part and so the amplitude of the solutions increases exponentially. If γ2 < 4mk then the eigenvalues are complex and so the solutions have an oscillating component. If γ2 = 4mk then there is one repeated, positive eigenvalue. But if γ2 > 4mk the system has one positive and one negative eigenvalue. The solution corresponding to the negative eigenvalue decays exponentially. The other solution increases exponentially. The general solution is a linear combination of these two solutions. As time increases, only the exponentially increasing component of the solution matters because the effect of the other component goes to zero.

In theory, the solution could consist purely of the exponentially decaying component. But in practice, if there is even the tiniest component of the exponentially increasing solution, this component will eventually dominate. A numerical solution, for example, would eventually be dominated by the exponentially increasing solution.

Now what about negative springs? Instead of being a restoring force, a negative spring would be a sort of amplifier, reinforcing rather than resisting displacement. The discriminant γ2 − 4mk will be positive if k is negative. There will be no oscillation because the eigenvalues have no complex part. Also, there will be one positive and one negative eigenvalue, and so the solutions grow exponentially as described above.

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9 thoughts on “Negative damping

  1. If I recall correctly, negative damping ‘resulting’ from the response of pedestrians on the millennium bridge over the River Thames here in London, England was the cause of the problems that required a retro-modification to stop it being the Wobbly Bridge, which is what it is now often called anyway.

  2. The negative damping case is very similar to the undamped, driven (at the natural frequency) case. The negative-damping cases is the *worse*, because as the amplitude of motion increases so does the effective driving force.

    I would guess that the Millenium bridge case mentioned above is somewhere in between negative damping and undamped driven cases: people walking over the bridge will adjust their movement in proportion to the bridge like negative damping, but their maximum response is clamped.

  3. Wouldn’t y^2>4mk yield 2 positive roots?

    r= [-y (+ or -) sqrt(y^2-4mk)]/2m
    if one of these were to be negative in the case of two real roots, this implies
    -y<sqrt(y^2-4mk) ,both sides are pos.
    00 so this is impossible and both of our roots must be positive.

  4. But the discriminant doesn’t tell you anything about whether the solutions are positive or negative, right?

  5. Aerodynamic flutter is a common example of negative damping. Think about a stop sign in a hurricane….

  6. I suppose Tacoma Narrows bridge failure was also due to this, rather than resonance (which my textbook says) ?

  7. I don’t know. I’ve heard contradictory things about the Tacoma Narrows bridge. It’s often presented as an example of resonance, but I’ve seen some writers say that’s not it.

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