Self-curvature

If you look at a sine wave, its curvature is sorta like its values. When sine is zero, the curve is essentially a straight line, and the curvature is zero. When sine is at its maximum, the function bends the most and so the curvature is at a maximum.

This makes sense analytically. The second derivative is something like curvature, and the second derivative of sin(x) is -sin(x). The negative sign suggests that if we look at signed curvature rather than absolute curvature, then the values of a sine curve are roughly proportional to the negative of the curvature at each point.

Here’s a plot showing sin(x) and its negative curvature.

Plot of a sine wave and its curvature

Steven Wilkinson wrote an article [1] addressing the question of whether there is a curve so that the curvature at each point is proportional to the value of the curve. The curvature of a graph of y = y(x) is

\kappa(x) = \frac{y''(x)}{(1 + y'(x)^2)^{3/2}}

and so a curve that is proportional to its curvature is a solution to the nonlinear differential equation

y(x) = \frac{a\, y''(x)}{(1 + y'(x)^2)^{3/2}}

General theory says that there should at least be a solution in a (possibly small) neighborhood of 0, but it’s not obvious a priori that interesting solutions exist. It turns out that if we pick the proportionality constant a = -1 and the initial conditions y(0) = 0 and y ‘(0) = √3 then we get a periodic solution that looks something like a sine.

The following Mathematica code will plot the function for us.

    s = NDSolve[
        {y''[x] = -y[x] (1 + y'[x]^2)^(-3/2), 
        y[0] == 0, y'[0] == Sqrt[3]}, 
         y, {x, 0, 10}]

    Plot[Evaluate[{y[x] /. s}], {x, 0, 10}]

The plot looks a lot like a sine wave. In fact, I imagine that when asked to draw a sine wave, most people would draw something that looks more like this than like an actual sine wave.

Related posts

[1] Steven Wilkison. Self-Curvature Curves. Mathematics Magazine, Vol. 82, No. 5 (December 2009), pp. 354-359

4 thoughts on “Self-curvature

  1. Almost. The exact value is given by an integral in the paper. To four decimal place the period is 4.9967.

Leave a Reply

Your email address will not be published.